Seymour, IAPublished Date: December 23, 2024Seymour is located in Wayne County, Iowa and has a population of 558. The poverty rate in Seymour is 17.5% and is higher than the US poverty rate of 11.5%. The U.S. poverty level for a family of four in 2023 is $31,200. The unemployment rate in Seymour is 2.4% while the Wayne County unemployment rate is 1.6%.
| | Population | |
|---|
| Male | | 50% |
| Female | | 50% |
| | Median Age (city/county) | |
|---|
| Seymour | | 50.5 |
| Wayne | | 41.9 |
| | Median Household Income (city/county) | |
|---|
| Seymour | | $40,547 |
| Wayne | | $58,257 |
| | Median Home Value (city/county) | |
|---|
| Seymour | | $63,597 |
| Wayne | | $98,897 |
| | Median Rent (city/county) | |
|---|
| Seymour | | $613 |
| Wayne | | $627 |
| | Poverty Rate (city/county) | |
|---|
| Seymour | | 17.5% |
| Wayne | | 13.3% |
Races and Ethnicity
▩ White 94.6%
▩ Black or African American 0%
▩ Asian 0%
▩ Native 0%
▩ Pacific 0%
▩ Other 0%
▩ Hispanic 0%
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