Sanford, FLPublished Date: November 23, 2024Sanford is located in Seminole County, Florida and has a population of 61,272. The poverty rate in Sanford is 12.8% and is higher than the US poverty rate of 11.5%. The U.S. poverty level for a family of four in 2023 is $31,200. The unemployment rate in Sanford is 5.2% while the Seminole County unemployment rate is 4.3%.
| | Population | |
|---|
| Male | | 50.1% |
| Female | | 49.9% |
| | Median Age (city/county) | |
|---|
| Sanford | | 35.6 |
| Seminole | | 39.6 |
| | Median Household Income (city/county) | |
|---|
| Sanford | | $59,181 |
| Seminole | | $79,490 |
| | Median Home Value (city/county) | |
|---|
| Sanford | | $239,135 |
| Seminole | | $327,022 |
| | Median Rent (city/county) | |
|---|
| Sanford | | $1,402 |
| Seminole | | $1,545 |
| | Poverty Rate (city/county) | |
|---|
| Sanford | | 12.8% |
| Seminole | | 9.6% |
Races and Ethnicity
▩ White 45.9%
▩ Black or African American 27.3%
▩ Asian 4.2%
▩ Native 0.2%
▩ Pacific 0%
▩ Other 9%
▩ Hispanic 26.3%
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