Sanibel, FLPublished Date: November 23, 2024Sanibel is located in Lee County, Florida and has a population of 6,420. The poverty rate in Sanibel is 9.5% and is lower than the US poverty rate of 11.5%. The U.S. poverty level for a family of four in 2023 is $31,200. The unemployment rate in Sanibel is 4.6% while the Lee County unemployment rate is 4.5%.
| | Population | |
|---|
| Male | | 47.7% |
| Female | | 52.3% |
| | Median Age (city/county) | |
|---|
| Sanibel | | 68.6 |
| Lee | | 49.1 |
| | Median Household Income (city/county) | |
|---|
| Sanibel | | $111,683 |
| Lee | | $69,368 |
| | Median Home Value (city/county) | |
|---|
| Sanibel | | $849,046 |
| Lee | | $288,575 |
| | Median Rent (city/county) | |
|---|
| Sanibel | | $1,003 |
| Lee | | $1,466 |
| | Poverty Rate (city/county) | |
|---|
| Sanibel | | 9.5% |
| Lee | | 11.7% |
Races and Ethnicity
▩ White 96.4%
▩ Black or African American 0.7%
▩ Asian 1%
▩ Native 0.6%
▩ Pacific 0%
▩ Other 0.4%
▩ Hispanic 0.9%
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